3n^2-3n/4n-4

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Solution for 3n^2-3n/4n-4 equation: 


n in (-oo:+oo)

3*n^2-(((3*n)/4)*n)-4 = 0

3*n^2+(-3/4)*n^2-4 = 0

9/4*n^2 = 4 // : 9/4

n^2 = 16/9

n^2 = 16/9 // ^ 1/2

abs(n) = 4/3

n = 4/3 or n = -4/3

n in { 4/3, -4/3 }

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